Find dy\dx :
____________
y=sinxcosx+tan3x^2+(secx)^2

Question

Find dy\dx :
____________
y=sinxcosx+tan3x^2+(secx)^2

experimentx · Answer

chain rule .. and make sinxcosx = 1/2 sin2x to make a little bit faster.

anonymous · Answer

I did that exactly as u said ,but he want me to solve it as a rate of change !!!!!

experimentx · Answer

first principle ??

anonymous · Answer

yea !

experimentx · Answer

I don't think it's going to be that easy. ,,, try simplifying as much as you can.

experimentx · Answer

especially this part.
tan3x^2+(secx)^2

anonymous · Answer

lol,i spent like 35 mins,doing it and then it was wrong cuz of something like a wrong sign in the middle of it .. ,i think i'am gonna try again , ty for helping :)

experimentx · Answer

No luck on wolf http://www.wolframalpha.com/input/?i=simplify+tan3x%5E2%2B%28secx%29%5E2

anonymous · Answer

oh ,lol..that gonna be looooooooooong

experimentx · Answer

is that variable x^2 ?? What ever it is ... this is going to be too ugly,
it's a crazy stuff.

anonymous · Answer

yea,I hate ma prof. he is just want to make sure that we are dumbs and he is the most brilliant ,lol...but i wont let that happen i will get it ..Just gimme 4 hours and then ima finish it

experimentx · Answer

you've got guts ... !!!