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My directions say to solve the exponential equation. 81^7x = 9
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write 81 as 3^4 and 9 as 3^2 then solve it
When you see these types of problems, look to see if you can make both sides have the same "base" 9 in this case. notice that 9^2 = 81 so you can rewrite this as \[ (9^2)^{7x} = 9^1 \]
use the rule \[ (x^y)^z = x^{yz} \] so you get \[ 9^{14x} = 9^1 \]
this means 14x = 1 solve for x
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