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Mathematics 13 Online
OpenStudy (anonymous):

x2 + 9x + 18 = 0 i know both x's are a three just unsure of the negative signs

OpenStudy (anonymous):

(x+6)(x+3)

OpenStudy (anonymous):

Are you using the crisscross method or decomposition method?

OpenStudy (anonymous):

sorry it is x=3 and x = 6 by the answer i just got i guess they are both positive

OpenStudy (anonymous):

If you aren't already using the criss cross method, I'd recommend that one, as it is much easier.

OpenStudy (anonymous):

x^2+9x+18 = 0 x^2+6x+3x+18=0 x(x+6) 3(x+6) (x+6)(x+3)

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