Question

solve on the interval [0,2pi) 1-cos theta=(2- sqrt 3)/2

Answer 1

\[1-\cos \theta=\frac{2-\sqrt{3}}{2}\]
\[2-2\cos \theta=2-\sqrt{3}\]
\[-2\cos \theta=-\sqrt{3}\]
\[\cos \theta=\frac{\sqrt{3}}{2}\]
\[\theta=\frac{\pi}{6}, \frac{11\pi}{6}\]