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OpenStudy (anonymous):
Solve on the interval [0, 2pi) (sinx -1)(2sin^2 x - 5sinx +2) Can somebody help me with this? I'm having a difficult time solving this for on the interval. Thanks!
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OpenStudy (alexwee123):
you're almost there just factor out (2sin^2 x - 5sinx +2) and then the rest is easy
OpenStudy (anonymous):
@alexwee123 if i factor it out, is that my answer?
OpenStudy (alexwee123):
no
OpenStudy (alexwee123):
here ill show you for one part of the answer |dw:1334293096420:dw|
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