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Mathematics 43 Online
OpenStudy (anonymous):

4. [8.01] Factor completely: 9a4b3 + 24a3b2 − 15a2b (4 points) 3a2b(3a2b2 + 8ab − 5) 3a2b3(3a2 + 8ab − 5) 3a2b(3a2b + 8ab − 5b) 3ab(3a3b2 + 8ab − 5a)

OpenStudy (alexwee123):

3a2b(3a2b2 + 8ab − 5)

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