The current I at time t seconds in a series circuit containing only a resistor
with resistance 10 ohm, an inductor with inductance 0.5 henry, and a
steady 12 volt battery connected at time t = 0 is given by the formula
I = (6/5) (1 − e^(−20t))

explain what happens to the current for t ≥ 0.

Question

The current I at time t seconds in a series circuit containing only a resistor
with resistance 10 ohm, an inductor with inductance 0.5 henry, and a
steady 12 volt battery connected at time t = 0 is given by the formula
I = (6/5) (1 − e^(−20t)) 

explain what happens to the current for t ≥ 0.

lalaly · Answer

this should be posted in physics or circuits

anonymous · Answer

it a calculation  question  it has something with differentiation :(

lalaly · Answer

|dw:1334309508537:dw|do kvl$$-12+0.5 \frac{dI}{dt}+10I=0$$