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Mathematics 15 Online
OpenStudy (anonymous):

Is this 2x2 matrix diagonalizeable? A= 4 -2 -1 5

OpenStudy (anonymous):

http://evergreen.loyola.edu/mpknapp/www/teaching/235-s01/review3/ follow this

OpenStudy (anonymous):

Using the characteristic equation I was able to determine that the eigenvalues are 6.3 and 2.7

OpenStudy (anonymous):

Then I tried to find the lin ind eigenvectors by following this: (A- eigenvalue*I) x1 = 0 x2 0

OpenStudy (anonymous):

to find eigenvectors solve this system: \[(A-\lambda I)v =0\]

OpenStudy (anonymous):

hmmm.. I get eigenvlues are 3 and 6

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