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Trigo question # ?
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This time, I can't even get one of the answers
you have two factors. one or both must be 0 for a solution (cos x -3 ) will never be zero for real x so you solve 3 sin x - 2 =0 sin x= 2/3 There will be 2 solutions between 0 and 2pi
So , i need to take arc sine?
yep
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Oh.. I know where I got wrong, thanks!!!
Be sure you are in radian mode. (but you know that already)
That's where I got wrong... No wonder why I couldn't find out the answer before. Thanks!!!
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