Question

Use the substitution method to find the solutions to the system of equations.
y=-x
y=x^2-3

Answer 1

-x = x^2 - 3

We can equal Y's.

Answer 2

y=-x
y=x^2-3

y = y
-x = x^2 - 3
0 = x^2 + x - 3
Use the quadratic formula.\[x = \frac {-b \pm \sqrt {b^2 - 4ac}}{2a}\]\[x = \frac {-1 \pm \sqrt {1 + 12}}{2}\]\[x = \frac {1}{2}(-1 - \sqrt {13}), x = \frac {1}{2} (-1 + \sqrt {13})\]

Answer 3

thank you