Question

GEOMETRY

Answer 1

its not opening !

Answer 2

why?

Answer 3

thanks, can u help me?

Answer 4

anyone else?

Answer 5

you should post it as a pdf or png so people without word can open it up

Answer 6

Use trig for the first one.

Answer 7

https://docs.google.com/viewer?url=http%3A%2F%2Fassets.openstudy.com%2Fupdates%2Fattachments%2F4f885ff9e4b0505bf08775e9-oatmeal123-1334337588131-unit9ex31.doc

Answer 8

do u use sine

Answer 9

thanks for doing that for me

Answer 10

can anyone please help me?

Answer 11

in the A part we have to find the angle right?

Answer 12

Find the angle BDA first.

Answer 13

isnt that 128

Answer 14

Im not sure, i think this is it.

Answer 15

okay

Answer 16

HELP PLEASE

Answer 17

For a start <CBA=<CBD + 76 degrees
<CBD= cos(inverse) 12.6/16 =38.05 dgrees
Or did you already work that part?

Answer 18

OH, WE USE cos, not sin

Answer 19

So did I

Answer 20

<CBA=114.05?

Answer 21

Lets see, 76 +38.05=114.05, we agree.

Answer 22

Is there a particular of the link that you are having trouble with?

Answer 23

well, i have trouble with sin and con, but let me see.... if I have a huge trouble with something

Answer 24

the second one

Answer 25

It is a problem with many facets!

Answer 26

CAN ANYONE HELP?

Answer 27

\[<ADB =180^{o}-90^{o}-76^{o}=14^{o}\]

Answer 28

thank u

Answer 29

Is there any other part that you are having difficulty with?

Answer 30

is 3. 38?

Answer 31

Let me check.

Answer 32

\[Sin ^{-1}=12.6/16=51.95^{o}\] where sin = opp/hyp, wouldn't you agree?

Answer 33

okay, then. Thank u

Answer 34

What did you get for AD?