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OpenStudy (anonymous):
x^2+y^2-6x+10y+34=0 is this a circle, a point or no real graph? if A CIRCLE find radius and center
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OpenStudy (anonymous):
\[x^2+y^2-6x+10y+34 = (x-3)^2 +(y+5)^2=0 \] It is the point (3,-5)
OpenStudy (anonymous):
ok thanks
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