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\frac { \sqrt [ 3 ]{ x } -\sqrt [ 3 ]{ 2 } }{ x-2 }
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\[\lim_{x \rightarrow 2}\frac { \sqrt [ 3 ]{ x } -\sqrt [ 3 ]{ 2 } }{ x-2 } \]
please help.
the answer is supposed to be \[\frac { 1 }{ 3 } \sqrt [ 3 ]{ 4 } \]
Plugging in 2 you get an indeterminant form, so you should be able to use l'hopitals rule
hint\[(a^3-b^3)=(a-b)(a^2+ab+b^2)\]
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haven't gotten to l'hopitals rule yet
so use my hint :)
yeah, thank you :))
finished. :P
:)
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