Question

H2C2O4 + SC(OH)3

Answer 1

\[H_2C_2O_4+Sc(OH)_3 \rightarrow\]This just looks like a neutralization reaction to me: oxalic acid and scandium hydroxide (I assume your capital "C" is supposed to be a lowercase "c"). The products of a neutralization reaction are always water an a neutral salt:\[2H^+(aq) + C_2O_4^{2-}(aq) + Sc^{3+}(aq) + 3OH^-(aq) \rightarrow H_2O(l)+Sc_2(C_2O_4)_3(s)\]Then we just need to balance the equation:\[3H_2C_2O_4(aq)+2Sc(OH)_3 \rightarrow 6H_2O(l)+Sc_2(C_2O_4)_3(s)\]