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Solve. 5 < x – 2 < 11
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add 2 to the ends to get the values for what x needs to be between in.
5<x-2<11 Add 2 to each section of the interval inequality because it does not contain the variable we are trying to solve for. 5+2<x<11+2 Add 2 to 5 to get 7. 7<x<11+2 Add 2 to 11 to get 13. 7<x<13 Convert the solution to set notation. (7,13)
just add +2 to all sides and you'll get: \[\LARGE 5+2 < x \;\;\;\;\;\;\underbrace{– 2+2}_{\text{This is 0}} < 11+2\]
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