Question

Hooke’s law states the distance of d a spring will stretch varies directly to the mass m of the object hanging from it. If a 5-kg weight causes it to fall 10 cm, how far will a 6-kg weight cause it to fall?

Answer 1

If distance 'd' varies directly with mass 'm' then this implies:\[d=k*m\]where 'k' is some constant.
you can find 'k' because you know d=10 when m=5.
that will then allow you to work out 'd' when m=6.