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Use logarithms to solve for x: 38^2x =109
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no
Didn't I just help you with this question literally 5 minutes ago?
\[\Large 2x = \log_{38} 109\]
do your own hmw.... don't blatantly ask for answers when you can do yourself
no its a diffrent one smart retricethe other one was asking significant digits... and feather you dont have to help dissmiss your self bumb feather
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significant digits? the answer is the same one i showed earlier
i have to put it in log form
|dw:1334359077216:dw|
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