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X 22 24 25 30 33 37 P(X) 0.16 0.09 0.18 0.12 0.24 0.21 What is the mean of this discrete random variable? That is, what is E(X), the expected value of X?
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this would be a weighted average right?
0.16 0.09 0.18 0.12 0.24 0.21 ----- 1.00
i think so
multiply each X by its P(X) and add up the results; then divide by .... cant remember. Sum of the Xs or sum of the P(x)s
so 1 is not the answer
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no, 1 aint the answer ... its the sum of the products of X*P(X)
E(X)=22(.16)+24(.09)+25(.18)+30(.12)+33(.24)+37(.21)
^^Continuing from above, 22(.16)+24(.09)+25(.18)+30(.12)+33(.24)+37(.21) = 29.47
lol, well, I was hoping trollz had enough wherewithal to deduce that part :)
ok i c the answer thanks
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