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Mathematics 7 Online
OpenStudy (anonymous):

X 22 24 25 30 33 37 P(X) 0.16 0.09 0.18 0.12 0.24 0.21 What is the mean of this discrete random variable? That is, what is E(X), the expected value of X?

OpenStudy (amistre64):

this would be a weighted average right?

OpenStudy (amistre64):

0.16 0.09 0.18 0.12 0.24 0.21 ----- 1.00

OpenStudy (anonymous):

i think so

OpenStudy (amistre64):

multiply each X by its P(X) and add up the results; then divide by .... cant remember. Sum of the Xs or sum of the P(x)s

OpenStudy (anonymous):

so 1 is not the answer

OpenStudy (amistre64):

no, 1 aint the answer ... its the sum of the products of X*P(X)

OpenStudy (amistre64):

E(X)=22(.16)+24(.09)+25(.18)+30(.12)+33(.24)+37(.21)

Directrix (directrix):

^^Continuing from above, 22(.16)+24(.09)+25(.18)+30(.12)+33(.24)+37(.21) = 29.47

OpenStudy (amistre64):

lol, well, I was hoping trollz had enough wherewithal to deduce that part :)

OpenStudy (anonymous):

ok i c the answer thanks

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