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Mathematics 11 Online
OpenStudy (cantfindasymptotewithbothhands):

-3/1-x < 9

OpenStudy (saifoo.khan):

Always remember, in inequatlities, the variable should be in +.

OpenStudy (saifoo.khan):

Please confirm your question, \[-\frac{3}{1-x} < 9\]This?

OpenStudy (mertsj):

I've got to give you a medal just because of your inability to find your asymptote.

OpenStudy (saifoo.khan):

o_O

OpenStudy (cantfindasymptotewithbothhands):

Yep Saifoo, that's it. I cross multiplied & distributed the numerator, then got stuck. I'm here: [9-9x]/-3

OpenStudy (saifoo.khan):

Help @Mertsj @Zarkon @CantFindAsymptoteWithBothHands , can't solve. :l

OpenStudy (mertsj):

\[\frac{-3}{1-x}=\frac{3}{x-1}<9\]

OpenStudy (saifoo.khan):

im stuck after this step!

OpenStudy (mertsj):

\[\frac{3}{x-1}-9<0\]

OpenStudy (saifoo.khan):

Awesome.

OpenStudy (mertsj):

\[\frac{3-9(x-1)}{x-1}<0\]

OpenStudy (mertsj):

\[\frac{3-9x+9}{x-1}<0\]

OpenStudy (mertsj):

\[\frac{9x+12}{x-1}<0\]

OpenStudy (mertsj):

Take it away saifoo

OpenStudy (saifoo.khan):

i still dont know how to get two answers. :l

OpenStudy (saifoo.khan):

9x + 12 < 0 and x - 1 < 0 ? x < -4/3 and x < 1 ? Now sure.

OpenStudy (mertsj):

I made a sign error. It's -9x+12 in the numerator.

OpenStudy (cantfindasymptotewithbothhands):

I messed up when I cross multiplied, was treating it as addition/subtraction rather than an equality/inequality

OpenStudy (mertsj):

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