The graph of y = ax^2 + bx + c has a maximum turning point at (2,5). It is true to say that. A. b^2 - 4 ac 0 Show me working out thanks.

Question

The graph of y = ax^2 + bx + c has a maximum turning point at (2,5). It is true to say that.
A.   b^2 - 4 ac <0
B.   b^2 =-4ac
C.   b^2 - 4ac = 0
D.   b^2 = 4ac
E. b^2 - 4ac > 0

Show me working out thanks.

amistre64 · Answer

using medals as bait is not against the rules perse, but it does come across as a bit tacky.

anonymous · Answer

kk. sorry.

amistre64 · Answer

its safe to say that a parabola with a max is upside down

amistre64 · Answer

|dw:1334381404231:dw|

since the max is above the x axis its also safe to say that it has 2 real zeros

amistre64 · Answer

when $$b^2-4ac>0$$ we have 2 real solutionss

amistre64 · Answer

hope that makes sense :)

anonymous · Answer

yep it does, thanks. I have several more problems if u don't mind helping me?