a 10g block with a charge of 8*10^-5 C is placed in an electric field E=(3000i-600j) N/C What are the magnitude and direction of the electrostatic forces on the block( relative to the positive direction of the x axis)? If the block is released from rest at the origin at time=0 what are the x and y coordinates at t=3.00 s

Question

anonymous · Answer

Electric field vector:
|dw:1334661470283:dw|
=> |dw:1334661520866:dw|
So you have the Electrostatic force vector, q > 0 means that force has the same direction of the Electric field vector - which is the vector sum of its two vector components
That force has the magnitude:
|dw:1334661614339:dw|