Question

sin(2cos^-1(-3/5)) is

Answer 1

let 2cos(inv) (-3/5) = A
cos A/2=(-3/5)
sinA=2sinA/2 * cosA/2
= 2sinA/2 * (-3/5)
=(-6/5) * sqrt(1-cos^2 (A/2))
= (-6/5)*(4/5)
= -24/25 is it correct???

Answer 2

@Sarkar - thanks...you got it right.:D

Answer 3

\[\sin2x=2sinxcosx=2(\frac{4}{5})(\frac{-3}{5})=\frac{-24}{25}\]

Answer 4

But did you get it??

Answer 5

yeah.

Answer 6

good...