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Trignometry Question
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AAD-wait for me...
Solve: [1/(sin 45 sin 46)] + [1/(sin 47 sin 48)] + ........................+ [1(sin 133 sin 134)]
good one...
The general term of the series is: \[t(n)=1/\sin x \sin (x+1)\] Now expand sin(x+1) using sin(A+B). Simplify, and you'll get a really simple general term/
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i think mani's approach is good!!!!
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