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solve equation logx – 116 = 4
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Are u sure the equation is correct ?
after the log the x-1 is small and then it's 16-4
\[\log_x-16=4\]?
Oh ,u mean Log(x-116)=4 ,or log(x) - 116=4
I guess it's like log(x-1)16-4
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\[\log_{x-1}-16=4\]?
oh yeah I 'm sorry after the 16 it is an equal sign
if that,the answer is3 or-1
\[\log_{x-1}16=4\]\[4^{x-1}=16\]\[4^{x-1}=4^{2}\]\[x-1=2\]\[x=3\] Why -1?\[4^{-2}={1\over16}\]
thank you!!
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oh,i was wrong...
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