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When graphing what happens to the graph due to the -x in this trigonometric transformation:
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\[y=\frac{1}{2} \cos (-x- \frac{\pi}{2})\]
Could someone walk me through the process on how I would graph this function?
The period is 2pi correct? Because B is 1, right?
cos(-theta) = cos(theta) and cos(x+pi/2) = -sin(x) that divided by 2. period=pi
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