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Mathematics 18 Online
OpenStudy (anonymous):

inverse trigonometry help - solve for x - 1) 3 arc sin[( 2x)/(1+x^2)] - 4 arc cos[ (1-x^2)/(1+x^2)] + 2 arc tan[(2x)/ (1-x^2)] = pi /3; 2) arc tan[(x-1)/(x-2)] + arc tan [(x-1)/(x-2)] = pi/4;

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