Question

Factor completely.

49t6 - 4k8

Answer 1

Both of those terms are perfect squares, what do you have to do?

Answer 2

is it \[\large 49t^6-4k^8\]

Answer 3

Actually these are the possible answers

Answer 4

(7t³ + 2k4)(7t³ - 2k4)
(7t³ - 2k4)(7t³ - 2k4)
(7t³ + 2k4)(7t³ + 2k4)

Answer 5

Ok you can write the question as

\[\large (7t^3)^2-(2k^4)^2\]
This is of the form\[\large a^2-b^2=(a+b)(a-b)\]

Now what can be the answer?