Question

evaluate where C is the line integral where C is the given curve:

Answer 1

\[\int\limits xy dS\] C: x=t^2 y = 2t 0<t<1

Answer 2

same procedure as before
1) change x and y to t's
2) \( ds = \sqrt{(\frac{dx}{dt})^2 + (\frac{dy}{dt})^2} dt\)

Answer 3

most likely
http://www.wolframalpha.com/input/?i=integrate+from+0+to+1+t%5E3+sqrt%281+%2B+4t%5E2%29