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Mathematics 30 Online
OpenStudy (anonymous):

factor check 4x^2 + 20x + 5y = xy solution (5 + x) (4x+y)? and i need help with this: 48 x 2^y + 20xz + 12xy + 5z

OpenStudy (anonymous):

* 5y + xy on the first one srry

OpenStudy (anonymous):

First one doesn't look right.

OpenStudy (anonymous):

what do you mean the solution?

OpenStudy (anonymous):

oh wait nvm, it's 5y + xy, it's right.

OpenStudy (anonymous):

Did you type that second one right? Could you retype that?

OpenStudy (anonymous):

yes i did 48x2^y + 20xz + 12xy +5z

OpenStudy (anonymous):

4x ( 12 xy + 5z ) + (12xy +5z) (12xy +5z) (4x + 1)

OpenStudy (anonymous):

Yea that's correct, you typed it incorrectly. I thought you meant 48 times 2 raised to exponent y.

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