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Find the vertex of the parabola with the given equation: x=1/8(y-2)^2+3 A) (2,3) B) (-2,-3) C) (-3, -2) D) (3,2)
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is (y-2)^2 multiplied to 1/8?
um no
D) (3,2)
vertex is (3, 2) it is in the form x = y^2 |dw:1334462318419:dw|
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