Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

Integral help! I'm just not seeing how to start to solve this integral.....its the integral of (ln(x+3))/(x+3)

OpenStudy (freckles):

did you try letting u=ln(x+3)

OpenStudy (anonymous):

then what would make the (x+3) on the bottom?

OpenStudy (freckles):

\[\int\limits_{}^{}\ln(x+3) \cdot \frac{1}{x+3} dx\] \[u=\ln(x+3) => du=\frac{1}{x+3} dx\]

OpenStudy (freckles):

Now just make those replacements and you will have something easy to integrate

OpenStudy (anonymous):

oh! herp derp to myself

OpenStudy (freckles):

:) I'm glad I could be a service

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
2 days ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
2 days ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!