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find the value of lim x->0 {(1-cos4x)/(1-cos6x)}
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\[\frac{\sin^22x}{\sin^23x} =\Large\left(\frac{\frac{2x}{2x}\sin2x}{\frac{3x}{3x}\sin3x}\right)^2 \] 4/9
gt it tnx, I needed to chek the answers
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