Question

12-x-x2?

Answer 1

Write it in the form \[ax^2+bx+c\]\[-x^2-x+12\]
Now you should find a number whose sum is -12 and sum is -1

Answer 2

Can you find it ?

Answer 3

i dont get it, is it -13?

Answer 4

well the product is (+12) but here that method cant be that easily done because of the negative sign of x2 so the sum may not be ( -1) !
i can solve it this way:
12-x-x2 = 12-4x + 3x - x2
= 4(3-x)+ x(3-x)
= (3-x)(4+x)

Answer 5

i understand now, thanks for your help :)

Answer 6

my pleasure XD