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vector cross product identity proof: curl(F x G)=(G.del)F - (F.del)G + F(del.G) - G(del.F)
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let F = fxi+fyj+fzk and G = gx i + gy j + gz k take cross product first, and then take again cross product with Del ... simplify it, you will get the Right Hand side. PS. this is gonna be ugly.
Yes pretty darn Ugly. But isn't there a simpler proof? I have tried what you have told.RHS doesn't come up
it does ,,, you have to look for the pattern
this is going to be the ugliest of the ugly. http://upload.wikimedia.org/wikipedia/en/math/b/6/8/b68f5acff7a101d7494bfea654e21c7a.png
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