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Mathematics 6 Online
OpenStudy (anonymous):

convert to polar form (x^2+y^2)^2 = 11(x^2 - y^2)

OpenStudy (experimentx):

put x = r cos(theta) and y = r sin(theta)

OpenStudy (anonymous):

then what?

OpenStudy (anonymous):

That's the conversion into polar form

OpenStudy (experimentx):

( r cos(theta)^2+ r sin(theta)^2)^2 = 11( r cos(theta)^2 - r sin(theta)^2)

OpenStudy (experimentx):

simplify ... !!! that will be your answer.

OpenStudy (anonymous):

kk

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