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find the greatest and least values of the function
f(x)=2x^2+2/x^2 for -2<=x<0,0
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equate differential to zero. and find x's for that. at those values maxima or minima exists. now, find double derivative at that x. negative double derivative means its a maxima, and a positive double derivative means its a minima
thx
http://www.wolframalpha.com/input/?i=f%28x%29%3D2x%5E2%2B2%2Fx%5E2++for+-2%3C%3D+x+%3C%3D2 Greatest seems infinity, critical points should give minimum
seems that x=0 is asymptote.
thx todays qns ovr :)
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