Question

Integrate[Tan^3[x]Sec^3[x]]

Answer 1

\[\sec^3x\tan^3x=\sec^2x\tan^2x(\sec x\tan x)=\sec^2x(\sec^2x-1)(\sec x\tan x)\]now this should be a little less scary

Answer 2

yeah, got it. Thanks.

Answer 3

welcome :)