Question

@imranmeah91 help fast!!

Answer 1

\[(3^{3}\sqrt{15}\div 5\sqrt{3})^{2}\]

Answer 2

help! its in fraction form..i couldnt find a fraction bar

Answer 3

3^3=27
Sqrt[15]=sqrt[5]* sqrt[3]

Answer 4

well use the "/" and complete the question

Answer 5

\[\large \left( \frac{3^3\sqrt{15}}{5\sqrt{3}} \right)^2\]

Answer 6

\[\large \sqrt{15}=\sqrt{5} \times \sqrt{3}\]

Answer 7

\[\large \left( \frac{3^3\sqrt{5} {\sqrt{3}}}{5\sqrt{3}} \right)^2\]

Answer 8

\[5=\sqrt{5} \times \sqrt{5}\]

Answer 9

\[\left( \frac{3^3}{\sqrt{5}} \right)^2 = \frac{3^6}{5}\]

Answer 10

this still confuses me..

Answer 11

\[\large \left( \frac{3^3\sqrt{5} {\sqrt{3}}}{5\sqrt{3}} \right)^2\]
got this much ?

Answer 12

yep

Answer 13

Sure ?
then
5 can be written as \(\sqrt{5} \times \sqrt{5} \)
\[\large \left( \frac{3^3\sqrt{5} {\sqrt{3}}}{\sqrt{5} \sqrt{5}\sqrt{3}} \right)^2\]

Answer 14

ok

Answer 15

Now you can cancel 1 Sqrt 5 and 1 sqrt 3 from numerator and denominator \[\large \left( \frac{3^3}{\sqrt{5}} \right)^2\]

Answer 16

did tht

Answer 17

It can be written as
\[\frac{(3^3)^2}{(\sqrt{5})^2}\]

Answer 18

yes

Answer 19

Now what do you get?

Answer 20

(27)^2 / 5

Answer 21

then i get..

Answer 22

Right!

Answer 23

=D

Answer 24

729/5?

Answer 25

Yup!!!

Answer 26

:D

Answer 27

ok now i have a new question..

Answer 28

Ok.. post it as new question ..this is lagging ..

Answer 29

kk