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If P(A∩B)=0.12,P(A)=0.33, and P(B)=0.43, find P(A∪B). A: 0.75 B: 0.60 C: 0.69 D: 0.64
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\[P(A \cup B)=P(A)+P(B)-P(A \cap B)\]
P(a union b) = P(A) + P(B) - P(A intersection b)
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