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Mathematics 27 Online
OpenStudy (anonymous):

Which function has removable discontinuity? a. h(x)=(x^2-x-2)/(x+1) b. g(x)=(2x-1)/x c. f(x)=(5x)/(1-x^2) d. p(x)=x/(x^2-x-2)

OpenStudy (anonymous):

not the bottom 3 for sure

OpenStudy (anonymous):

because for the bottom 3, the zero of the denominator is not also a zero of the numerator

OpenStudy (anonymous):

\[ x^2-x-2 =(x+1)(x-2) \]

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