the length of a rectangle is 5 m more than twice
its width ,and the area of the rectangle is 88m^2 .
find the dimensions .

length :
width :

Question

the length of a rectangle is 5 m more than twice 
its width ,and the area of the rectangle is 88m^2 . 
find the dimensions .

 length :
 width :

lgbasallote · Answer

l = 5 + 2w
w = w
a = lw
a = (5+2w)(w)

anonymous · Answer

a=2w^2+5w

lgbasallote · Answer

now equate that to your area then use completing square/quadratic formula

anonymous · Answer

i dont know how to use it

lgbasallote · Answer

2w^2 + 5w = 88

2w^2 + 5w - 88 = 0

a = 2; b = 5; c = -8

quadratic form:

x = -b +/- sqrt (b^2 - 4ac) all over 2a

anonymous · Answer

i just need the answer of the length and the width !!

lgbasallote · Answer

then you better start substituting values ^_^

directrix · Answer

Continuing from above:

2w^2 + 5w - 88 = 0  will factor
(w+8)(2w-11) = 0
Zero Product Property
w +8 = 0 or 2w -11 = 0
w = -8 or 2w = 11
w = -8 (discard for this application) or w = 11/2 = 5.5
w = 5.5 meters and Length = 2(5.5) + 5 = 16 meters