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|dw:1334553973707:dw|
Please explain using 2(bh/2)+Ph
http://math.about.com/od/formulas/ss/surfaceareavol_6.htm ... I don't get that formula :(
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not sure... let's see.
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The height, h, is:\[h=\sqrt{5^2-4^2}=3 \]The sum of the triangle areas is 2(bh/2)=\[2\left(\frac{8*3}{2}\right)=24 \]The area of the sides and the floor is\[2*(17*5)+(17*8)=306 \]Adding up all of the areas yields 330 square units.
I think I ahve the formula figured out! @robtobey would you like to know?
*have
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