A baseball is hit with a speed of 30m/s at an angle of 42 degrees. It lands on the flat roof of a 14.0, tall nearby building. If the ball was hit when it was 1.4m above the ground, what horizontal distance does it travel before it lands on the building?

Question

anonymous · Answer

I think I have the soluion, but the work is quite long, so please bare with me...

anonymous · Answer

|dw:1334586017031:dw|

What I know is:

$$g=9.80m/s^2  $$
$$ v _{0y}=(30m/s)\sin(42)=20.07m/s$$
$$d=-1.4m$$