Question

Resolve into Partial fractions
xcube divided by 1-xcube

Answer 1

right is it x^2 under is 1-x^2 ?

Answer 2

Actually its X raise to power 3 by 1-Xraise to power 3

Answer 3

\[\LARGE \frac{x^3}{(1-x)^3}\] this or
\[\LARGE \frac{x^3}{1-x^3}\] this ?

Answer 4

\[\LARGE \frac{x^3}{1-x^3}=\frac{x^3}{1^3-x^3}\]
\[\LARGE \frac{x^3}{(1-x)(1^2+x\cdot 1+x^2)}=\frac{x^3}{(1-x)(1+x+x^2)}\]
\[\LARGE \frac{x^2}{(1-x)}\cdot \frac{x}{(1+x+x^2)}=...\]
go on...

Answer 5

ok, Thanks :)