Question

1. The diagonal of a square is 8√2. Find the length of a side of the square.

2. 2x√3/2x times √8x-cubed/6

Answer 1

2. \[2x \sqrt{\left(\begin{matrix}3 \\ 2x\end{matrix}\right)} \times \sqrt{\left(\begin{matrix}8x ^{3} \\6\end{matrix}\right)}\]

Answer 2

Okay, I got 1. Now i just need 2.

Answer 3

Okay
\[2x* \frac{\sqrt{3}}{\sqrt{2x}} * \frac{\sqrt{8x^2}}{\sqrt{6}} =\sqrt{2x}*\sqrt{3}* \frac{\sqrt{8x^2}}{\sqrt{6}} \]
Since \[2x=\sqrt{2}*\sqrt{2}*\sqrt{x}*\sqrt{x}=\sqrt{2x}*\sqrt{2x}\]

And\[\sqrt{6}=\sqrt{2}*\sqrt{3}\]
\[\sqrt{8}x*\sqrt{x}=x \sqrt{8x}\]

Answer 4

Wow.....thank you

Answer 5

Anytime :)