Question

precalc!

Answer 1

sin(2t)-sin(t)=0
sin(2t) = 2sin(t)cos(t)

2sin(t)cos(t)-sin(t)=0
sin(t) [ 2cos(t) -1] = 0
sin(t) = 0
t = 0, pi

2cos(t)-1=0
2cos(t)=1
cos(t)=1/2
t=pi/3, 5pi/3

so t=0, pi/3, pi, 5pi/3