Two people are carrying a box. One person exerts a force of 123 pounds at an angle of 47.9° with the horizontal. The other person exerts a force of 94 pounds at an angle of 54.6°. Find the weight of the box.

Question

Two people are carrying a box.  One person exerts a force of  123 pounds at an angle of  47.9° with the horizontal.  The other person exerts a force of  94 pounds at an angle of  54.6°.  Find the weight of the box.

anonymous · Answer

if the box does not move then:
sum of forces on the x axis is zero
sum of forces on the y axis is zero

anonymous · Answer

you might also want to convert the force from pounds to newtons, so your mass would be in kilograms

anonymous · Answer

ok, thank you.
 can you show me how to do that?

anonymous · Answer

ill try my best
F1= force of the person exerting 123 pounds
F2=the other person exerting 96 pounds
assuming that the people are on the other side and the exert the force toward themselves and above
cos(theta)=adjacent/hypotenuse
adjacent is hypotenuse x cos(theta)
sum of the force on the x direction
F1cos(theta) - F2cos(theta)=ma=0

anonymous · Answer

when you calculate that, what do you find the weight of the box to be?

anonymous · Answer

im just showing the process. i might be able to do the whole number tomorrow, im getting sleepy

anonymous · Answer

alright thank you anyhow!