Question

sorry, another heaviside laplace transform (attachment)

Answer 1

\[f(t)=[2t-\sin(t)][H(t-0)-H(t-pi)]\]

Answer 2

\[f(t)=2tH(t-0)-2tH(t-pi)-\sin(t)H(t-0)+\sin(t)H(t-pi)?\]

Answer 3

\[f(t)=\]\[2(t-0)H(t-0)-2(t-\Pi)H(t-\Pi)-2\Pi H(t-\Pi)-\sin(t-0)H(t-0)\]\[+\cos(\Pi)\sin(t-\Pi)H(t-\Pi)+\sin(\Pi)\cos(t-\Pi)H(t-\Pi)?\]