Question

For the equation find the equation of the graph that is parallel and perpendicular that passes through the specified point. Then graph the equations

The equation is 3x - y = 9

So i have the equations

y = 3x + 9
y = 3x - 2
y = 1/3x + 4/3

but I am confused on how to graph it

Answer 1

3x - y = 9
so y = 3x-9
perpendicular: y =-1/3x -9

Answer 2

@MSFFL the equation for perpendicular line, that you have prepared is incorrect, to the best of my knowledge.

Answer 3

I got the 3 equation by doing the following

The specified points are (1,1)

1. 3x - y = 9
2. -y = 3x + 9
3. y = 3x -9 (Slope = 3)

So now
1. y = mx+b
2. 1 = 3(1) + b
3. b = -2

Equation is y = 3x - 2

for perpendicular

Slope = -1/3

1. y = mx + b
2. 1 = -1/3(1) + b
3. b = 4/3

Equation is y = -1/3x + 4/3

Answer 4

looks ok

Answer 5

Now how do I graph it?

Answer 6

slope m means : for 1 horizontal unit you go up m vertical units
the last term in y = mx + b equation, b, is the point where you intersect y axis

Answer 7

Here are the graphs,