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OpenStudy (anonymous):
Solve.
6xy^3z • 3x^2yx^2
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OpenStudy (anonymous):
you'll have to use this formula:
\[\LARGE x^n\cdot x^m=x^{n+m}\]
... example:
\[\LARGE ax^n\cdot bx^m=(a\cdot b)x^{n+m}\]
OpenStudy (anonymous):
can you do it ?
OpenStudy (anonymous):
It Sent This : \[\LARGE x^n\cdot x^m=x^{n+m}\]
... example:
\[\LARGE ax^n\cdot bx^m=(a\cdot b)x^{n+m}\]
OpenStudy (anonymous):
you did what? ... O_O did you copied my post? or retyped it? if you copied , how did you do that ? O_O :A :)
OpenStudy (anonymous):
I Copied It Ctrl+C
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OpenStudy (anonymous):
do you know to solve your problem? (To me it didn't work just Ctrl+C ) :S
OpenStudy (anonymous):
(Ya Just Ctrl then C) I Don't Think I Can Solve It
OpenStudy (anonymous):
\[\LARGE 6xy^3z\cdot 3x^2yx^2=18x^{2+2+1}y^{3+1}z\] how about now ? :)
OpenStudy (anonymous):
6xy^3z * 3x^2yx^2 = 18x^(2+2+1)y^(3+1)z ...??
OpenStudy (anonymous):
sum exponents ...
18x^(2+2+1)y^(3+1)z =18x^(5)y^(4)z
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OpenStudy (anonymous):
18x^(5)y^(4)z =18x^(5)y^(4)z ?
OpenStudy (anonymous):
18x^(5)y^(4)z is the final answer..
OpenStudy (anonymous):
Thank You For Ur Wonderful Help
OpenStudy (anonymous):
My pleasure ...
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